What is the relationship between the energy of the vacuum and the Cosmological Constant?

The vacuum energy is a property of space-time which is so fundamental that its value will be the same as observed by anyone. It is called a relativistic invariant. In general relativity, the only way you can build such an invariant quantity into the relativistic equation for gravitation is to multiply the constant by the so-called 'metric tensor' which also represents both the strength of the gravitational field and the geometric properties of space-time. So, with out knowing anything about the vacuum energy other than it is a relativistic invariant, we can add it as a term to Einstein's equation for gravity. When we do so, we discover that nay such 'vacuum energy' terms added to space-time have exactly the same mathematical form as the famous 'cosmological constant' term added by Einstein back in 1917 as a form of 'anti-gravity' to make the universe static and eternal. Numerically, the cosmological constant (lambda) can be reinterpreted as the density of vacuum energy caused by the 'scalar field':

            8 pi G Rho
lambda =  -------------
               3
where Rho is the density of energy ( grams/cc or ergs/cc) and G is the constant of gravity. The problem is that when physicists try to predict the magnitude of the vacuum energy, they get an answer that is 10^120 times larger than the observational limit on lambda by astronomers. Physicists are hard at work finding a 'beautiful' way for the universe to make lambda go away!
Copyright 1997 Dr. Sten Odenwald
Return to Ask the Astronomer.